Area= INT (f(x)-g(x))dx frm -5 to 8
= INT (.4x^2+5-x)dx
= .4/3 x^3 + 5x-x^2/2 on limits
check my thinking.
Find the area enclosed between
f(x)=0.4x^2+5
and
g(x)=x
From x=-5 to x=8
1 answer
f(x)=0.4x^2+5
and
g(x)=x
From x=-5 to x=8
1 answer