Do you mean between x = 1 abd x = 3?
Is the second term 1/(4x^2) or (1/4)x^2?
Find the arc length given the equation y=(x^4/8)+(1/4x^2) [1,3]
2 answers
Yes between the interval x=1 and x=3 and in the second term it is 1/(4x^2)