FIND THE ANGLES BETWEEN 0degree and 360degree whose sine is 0.9962
2 answers
Give me the solution
your reference angle is θ such that
sinθ = 0.9962
θ = 85°
sine is positive in QI and QIIso your solutions are
θ and 180-θ
sinθ = 0.9962
θ = 85°
sine is positive in QI and QIIso your solutions are
θ and 180-θ