Find the acceleration of the block of mass M = 5.06 kg in the figure below. (Take m = 4.24 kg.)
10 answers
If you pasted a diagram, that does not work here.
//d2vlcm61l7u1fs.cloudfront.
net/media%2Ff38%2Ff385e045-5c9f-4f53-8ded-aa29a4d1d55c%2FphpOMgUlO.png
net/media%2Ff38%2Ff385e045-5c9f-4f53-8ded-aa29a4d1d55c%2FphpOMgUlO.png
This the rightlink //d2vlcm61l7u1fs.cloudfront.
net/media%2Ff38%2Ff385e045-5c9f-4f53-8ded-aa29a4d1d55c%2FphpOMgUlO.png
net/media%2Ff38%2Ff385e045-5c9f-4f53-8ded-aa29a4d1d55c%2FphpOMgUlO.png
Say TL = tension in left string
Say TR = tension in right string
a = acceleration of all to right
On the middle mass
F = TR - TL - 0.10*2*g = 2 a
TR = 5.06 (g-a)
TL = 4.24 (g+a)
so
5.06(g-a)-4.24(g+a) =2 a + 0.2g
0.82 g - 9.3 a = 2 a + 0.2 g
11.3 a = 0.62 g
a = .055 g
if g = 9.81 m/s^2
then
a = 0.538 m/s^2
Say TR = tension in right string
a = acceleration of all to right
On the middle mass
F = TR - TL - 0.10*2*g = 2 a
TR = 5.06 (g-a)
TL = 4.24 (g+a)
so
5.06(g-a)-4.24(g+a) =2 a + 0.2g
0.82 g - 9.3 a = 2 a + 0.2 g
11.3 a = 0.62 g
a = .055 g
if g = 9.81 m/s^2
then
a = 0.538 m/s^2
No problem, was able to get there from first link.
you are so coolDamon
where did you get 0.2g from?
How 5.06(g-a)become 0.82 g and 4.24(g+a)become 9.3
where did 0.62g come from?
I don't get it can you do it in number form?
1 answer