h'(x) = -2/x^2
a function is increasing when its first derivative is positive, and
a function is decreasing when its first derivative is negative.
now look at our derivative, notice the bottom is a square of x, so no matter what you put in, the result will be positive, and this is divided into -2.
so what result will we get??
also notice that both the original and the derivative are undefined for x=0
Find the (a) the local extrema, (b) the intervals on which the function is increasing, (c) the interval on which the function is decreasing
h(x)=2/x
1 answer