Ask a New Question

Find the a)partial pressure of ethylene oxide and b)the total gas pressure, after 30 hours in a reaction vessel at 415C if the initial pressure of ethylene oxide is 782mmHg. k= 2.05x 10^-4 t(1/2)=56.3

Part A)
I converted hours to seconds, and used the formula ln(Pa)t = 108000s x k + ln782

I got the correct answer which is 1.9x10^-7mmHg.

But I don't know how to do part B

Ask a New Question or answer this question.

Similar Questions

mole fraction is equal to partial pressure divided by the total pressureTotal pressure= sum of partial pressure use PV=nRT where
1. 0 answers
Air in the alveoli has a partial pressure of nitrogen of 569 mm Hg, oxygen is 104 mm Hg, water is 40 mm Hg, Carbon dioxide is 47
1. 1 answer
If N2 is added to a balloon that contains O2 (partial pressure 450 mm Hg) and CO2 (partial pressure 150 mm Hg) to give a total
1. 0 answers
If N2 is added to a balloon that contains O2 (partial pressure 450 mm Hg) and CO2 (partial pressure 150 mm Hg) to give a total
1. 1 answer

more similar questions