95% = mean ± 1.96 SEm
SEm = SD/√n
Find the 95 percent range for the sample mean, assuming that each sample is from a normal
population.
a. ì = 200, ó = 12, n = 36
b. ì = 1,000, ó = 15, n = 9
c. ì = 50, ó = 1, n = 25
1 answer