Find the 8th term of a G. P whose 3rd and 6th are 1/2 and 1/32 respectively.

Answer 1

r^3 = (1/32)/(1/2) = 1/16
a_8 = a_6 * r^2 = 1/32 (1/16)^(2/3) = = 1/256 ∛2

I suspect a typo