Find the 19th term of the sequence described below, where n represents the position of a term in the sequence. an = 81n − 56 Submit

Answer 1

To find the 19th term of the sequence defined by \( a_n = 81n - 56 \), we need to substitute \( n = 19 \) into the formula.

\[ a_{19} = 81(19) - 56 \]

Calculating \( 81 \times 19 \):

\[ 81 \times 19 = 1539 \]

Now substitute this value back into the equation:

\[ a_{19} = 1539 - 56 \]

Now calculate \( 1539 - 56 \):

\[ 1539 - 56 = 1483 \]

Thus, the 19th term of the sequence is:

\[ \boxed{1483} \]