Find the 10th term from the sequence 7,10,13...130

Answer 1

The sequence has a common difference of 3, so we can find the $n$th term using the formula $a_n = a_1 + (n-1)d$, where $a_1=7$ and $d=3$. Plugging in $n=10$, we get:

$a_{10} = 7 + (10-1)3 = 7 + 27 = \boxed{34}$