Find tan(3 theta) in terms of tan theta
Use the formula
tan (a + b) = (tan a + tan b)/[1 - tan a tan b)
in two steps. First, let a = b = theta and get a formula for tan (2 theta).
tan (2 theta) = 2 tan theta/[(1 - tan theta)^2]
Then write down the equation for
tan (2 theta + theta)
Are you sure you are supposed to use complex numbers to answer this question? My previous answer used a trigonometric identity. I don't see a way to use complex numbers, but there probably is a way.
Exp(3 i theta) = [Exp(i theta)]^3 --->
cos(3 theta) = c^3 - 3cs^2
sin(3 theta) = 3c^2s - s^3
where c = cos(theta) and s = sin(theta)
This means that:
tan(3 theta) =
[ 3c^2s - s^3]/[c^3 - 3cs^2]
divide numerator and denominator by c^3:
tan(3 theta) =
[ 3t - t^3]/[1 - 3t^2] =
where t = tan(theta)
Thanks everyone for your help. Yes I did have to use complex numbers. Thanks Count I really should have seen your method for myself as I had found cos 3theta and sin 3 theta in an earlier problem.
Thanks again Jake
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