just sub in2x+2 for y
x^2+3x-4 = 2x+2
x^2+x-6 = 0
(x+3)(x-2) = 0
...
or, without solving, you could just check each of the choices... duh
Find solutions to the system
y=x^2+3x-4
y=2x+2
A (-3,6)and(2,-4)
B (-3,-4) and (2,6)
C (-3,-4) and (-2,-2)
D no solutions
2 answers
ohhhhhhh i see what you mean thank you