Find Solution set of underrootx=6x.here under root x means positive square root of x.

Answer 1

sqrt (x) = 6 x

x = 36 x^2 but may introduce false solution along with correct one

36 x^2 -x = 0

x(36 x -1) = 0

x = 0 or x = 1/36

x = 0 works, 0 = 0

if x = 1/36
1/6 = 6/36 yes that also works

so x = 0 or x = 1/36