Ask a New Question
Menu

Find sin (x-y) if sinx = -2/5 and siny = 2/3 X is in quadrant IV, and y is in quadrant I

1 answer

sinx = -2/5, x is in IV , so
cosx = √21/5

siny = 2/3 , y is in I , so
cosy = √5/3

sin(x-y) = sinxcosy - cosxsiny
= (-2/5)(√5/3) - √21/5)(2/3)
= ( -2√5 - 2√21)/15
Similar Questions
    1. answers icon 2 answers
  2. Sin(X-y)sin(x+y)=sin^2 x - sin^2 ywork on one side only...so i worked on the right =(sinx-siny)(sinx+siny) does that equal
    1. answers icon 1 answer
  3. Sin(X-y)sin(x+y)=sin^2 x - sin^2 ywork on one side only...so i worked on the right =(sinx-siny)(sinx+siny) does that equal
    1. answers icon 1 answer
  4. Verify each identitysin^x+siny/sinx-siny=tan(x+y/2) (times) cot(x-y/2)
    1. answers icon 0 answers
more similar questions