find point(s) on the graph of the function f(x) = x^3 - 2 where the slope is 3

Answer 1

f' = 3x^2 - 2

3x^2 - 2 = 3
x^2 = 5/3

x = +/- sqrt (5/3)

Answer 2

thank you very much

Answer 3

You are welcome.