If QR divides ∠PQT, then
10x-9 + 5x = 2x+6
If QT divides ∠PQR, then
10x-9 = 5x + 2x+6
Since you did not describe the figure, you must decide which case holds. In any case, clearly, one angle is the sum of the other two, so just do the math.
Find m∠RQT if m∠PQR = (10x – 9) °, m∠RQT = (5x) °, and m∠PQT = (2x + 6) °
m∠PQR= degree
1 answer