m∠ABC = m∠B - m∠A
Given A (2x), B (5x+5), and C are collinear.
If ∠ABC = 130°, then
130 = (5x+5) - 2x
130 = 3x + 5
125 = 3x
x = 41.67
m∠ABC = m∠B - m∠A
m∠ABC = (5x+5) - 2x
m∠ABC = (5(41.67)+5) - 2(41.67)
m∠ABC = 208.35 + 5 - 83.34
m∠ABC ≈ 130.01°
Therefore, the angle ∠ABC is approximately 130.01°.
Find m∠ABC.
A (2x) D B(5X+5) C
130°
50°
60°
25°
1 answer
1 answer