Substitute x = 1 - t and expand the squareroots in series using the formula:
sqrt[1 + y] = 1 + y/2 + O(y^2)
You should then find that the limit is 1/2
Find limit X approaches 1 for
((5-X)^.5 -2)/((2-X)^.5 -1)
e-mail address: mark.hultgren
Thank you.
2 answers
or
Multiply by ((5-X)^.5 + 2)/((5-X)^.5 + 2)*((2-X)^.5 + 1)/((2-X)^.5 + 1)
which reduces your question to
Limit ((2-X)^.5 + 1)/((5-X)^.5 + 2) as x-->1
= 2/4
= 1/2
BTW, it is strongly suggested that you do not put your email or personal information in these postings
Multiply by ((5-X)^.5 + 2)/((5-X)^.5 + 2)*((2-X)^.5 + 1)/((2-X)^.5 + 1)
which reduces your question to
Limit ((2-X)^.5 + 1)/((5-X)^.5 + 2) as x-->1
= 2/4
= 1/2
BTW, it is strongly suggested that you do not put your email or personal information in these postings
0 answers