as x->c, the limit is c^2+5
However, the limit as x->1 is 6, but F(1) = 1, so F is not continuous there.
Find Limit : Let F(x) = ( x^2 + 5; x does not equal 1)(1; x=1)
2 answers
So the limit of the function as x approaches c is six for the first set and the second one f(1) equals one does not have a limit?