Find limit as x approaches 0 [7x/(sqrt(x+4)-2)]

Answer 1

how about L'Hopital's Rule

limit = 7/( (1/2)(x+4)^-(1/2) )
= 14(√(x+4)
= 14(2) as x---> 0
= 28

Answer 2

How do I solve it without L'Hospital's Rule?

Answer 3

Nevermind. I got it