Find left-parenthesis f dot g right-parenthesis left-parenthesis x right-parenthesis when lower f left-parenthesis x right-parenthesis equals Start Fraction Start Root x plus 3 End Root over x End Fraction and lower g left-parenthesis x right-parenthesis equals Start Fraction Start Root x plus 3 End Root over 2 x End Fraction.

(1 point)
Responses

left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction x squared plus 6 x plus 9 over 2 x squared End Fraction
Image with alt text: left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction x squared plus 6 x plus 9 over 2 x squared End Fraction

left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction Start Root x plus 3 End Root over 2 x squared End Fraction
Image with alt text: left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction Start Root x plus 3 End Root over 2 x squared End Fraction

left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction x plus 3 over 2 x squared End Fraction
Image with alt text: left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction x plus 3 over 2 x squared End Fraction

left-parenthesis lower f dot lower g right-parenthesis left-parenthesis x right-parenthesis equals Start Fraction x squared plus 9 over 2 x squared End Fraction

1 answer

To find \((f \cdot g)(x)\), we start by determining the product of the two functions \(f(x)\) and \(g(x)\).

Given: \[ f(x) = \frac{\sqrt{x + 3}}{x} \] \[ g(x) = \frac{\sqrt{x + 3}}{2x} \]

The product \( (f \cdot g)(x) \) can be calculated as follows: \[ (f \cdot g)(x) = f(x) \cdot g(x) = \left(\frac{\sqrt{x + 3}}{x}\right) \cdot \left(\frac{\sqrt{x + 3}}{2x}\right) \]

Now, we multiply the numerators and the denominators: \[ = \frac{\sqrt{x + 3} \cdot \sqrt{x + 3}}{x \cdot 2x} = \frac{x + 3}{2x^2} \]

So, we find that: \[ (f \cdot g)(x) = \frac{x + 3}{2x^2} \]

Therefore, the correct response is: \[ \boxed{\frac{x + 3}{2x^2}} \]