find indefinite integral [(sinx)^3]*[(cosx)^3] dx

i got 1/192 * ((cos(6x)-9cos(2x)) + C

but this isnt right. explain plz? thnx

1 answer

You may want to show your work to know how you got your answer.

The good news is that your indefinite integral is correct, but off by 1/24, which can be absorbed in the integration constant.

Depending on how you integrated, it could give equivalent results of:
(3sin(x)^4-2sin(x)^6)/12, or
(2cos(x)^6-3cos(x)^4)/12

The latter is your answer less 1/24, the constant.