To calculate the number of ways four men and two women can stand in a line with the two women at the front, we can consider the women as a single entity. This reduces the problem to arranging five people in a line.
The number of ways to arrange five people in a line is 5!, which is equal to 5 x 4 x 3 x 2 x 1 = 120.
Therefore, there are 120 ways for four men and two women to stand in a line with the two women at the front.
Find how many ways four men and two women can stand in a line if the two women must be at the front
1 answer