To find \( g(x) \), which is the translation of \( f(x) = x^2 \) 7 units down, we need to subtract 7 from the function.
Starting with the original function:
\[ f(x) = x^2 \]
To translate this down by 7 units, we modify the function as follows:
\[ g(x) = f(x) - 7 = x^2 - 7 \]
Now, we need to express this in the form \( a(x - h)^2 + k \).
In this case, since \( f(x) \) is already in the vertex form \( a(x - h)^2 + k \):
\[ g(x) = 1(x - 0)^2 - 7 \]
Here, \( a = 1 \), \( h = 0 \), and \( k = -7 \).
Thus, we can write:
\[ g(x) = 1(x - 0)^2 - 7 \]
Final answer:
\[ g(x) = 1(x - 0)^2 - 7 \]
Or simplified:
\[ g(x) = (x - 0)^2 - 7 \]
So, in the requested form:
\[ g(x) = 1(x - 0)^2 - 7 \] or simply:
\[ g(x) = (x - 0)^2 - 7 \]
This gives the values:
- \( a = 1 \)
- \( h = 0 \)
- \( k = -7 \)