find g(1)+g(2)+g(3)+...+g(50) given that g(x)=13-5x

Answer 1

this is simply an arithmetic series where
a = 8
d = -5
n = 50

sum(n) = (n/2)[2a + (n-1)d)]
sum(50) = (50/2)[16 + 49(-5)]
= 25[-229]
= -5725