Find ​(fcircle​g)(x) and ​(gcircle​f)(x).

​f(x)equals5xminus8​, ​ g(x)equals4minus4x
Question content area bottom
Part 1
​(fcircle​g)(x)equals
  
enter your response here ​(Simplify your​ answer.)
Part 2
​(gcircle​f)(x)equals
  
enter your response here ​(Simplify your​ answer.)

1 answer

To find \((f \circ g)(x)\) and \((g \circ f)(x)\), we first need to understand how function composition works. The notation \((f \circ g)(x)\) means that we will evaluate \(g(x)\) and then plug that result into \(f\). Similarly, \((g \circ f)(x)\) means that we will evaluate \(f(x)\) and then plug that result into \(g\).

Given:

  • \(f(x) = 5x - 8\)
  • \(g(x) = 4 - 4x\)

Part 1: Calculate \((f \circ g)(x)\)

  1. First, find \(g(x)\): \[ g(x) = 4 - 4x \]

  2. Now, substitute \(g(x)\) into \(f\): \[ (f \circ g)(x) = f(g(x)) = f(4 - 4x) \]

  3. Now apply the function \(f\): \[ f(4 - 4x) = 5(4 - 4x) - 8 \] \[ = 20 - 20x - 8 \] \[ = 12 - 20x \]

So, \((f \circ g)(x) = 12 - 20x\).

Part 2: Calculate \((g \circ f)(x)\)

  1. First, find \(f(x)\): \[ f(x) = 5x - 8 \]

  2. Now, substitute \(f(x)\) into \(g\): \[ (g \circ f)(x) = g(f(x)) = g(5x - 8) \]

  3. Now apply the function \(g\): \[ g(5x - 8) = 4 - 4(5x - 8) \] \[ = 4 - 20x + 32 \] \[ = 36 - 20x \]

So, \((g \circ f)(x) = 36 - 20x\).

Summary of the results:

  • \((f \circ g)(x) = 12 - 20x\)
  • \((g \circ f)(x) = 36 - 20x\)

You can enter these results in the respective response fields as:

  • \((f \circ g)(x) = 12 - 20x\)
  • \((g \circ f)(x) = 36 - 20x\)
Similar Questions
  1. Find ​(fcircle​g)(x) and ​(gcircle​f)(x).​f(x)equals5xminus5​, ​ g(x)equals6minus2x Question content area bottom
    1. answers icon 1 answer
  2. Question content area topPart 1 Find​ (a) ​(fcircle​g)(x) and​ (b) ​(gcircle​f)(x). ​f(x)equals7 x squared​;
    1. answers icon 1 answer
  3. Find​ (a) ​(fcircle​g)(x) and​ (b) ​(gcircle​f)(x).​f(x)equalsStartRoot x minus 4 EndRoot​; ​g(x)equals5 x
    1. answers icon 1 answer
  4. Find​ (a) ​(fcircle​g)(x) and​ (b) ​(gcircle​f)(x).​f(x)equalsStartRoot x minus 1 EndRoot​; ​g(x)equals4 x
    1. answers icon 1 answer
more similar questions