find f'(x) if f(x)=x^2*e^x*(3x-1)^3

Answer 1

f(x) = (x^2) (e^x) (3x-1)^3

if y = uvw
then y' = u'(vw) + v'(uw) + w'(uv)

I see 3 factors in f(x) to match that pattern.
Does not look difficult, just carefully follow the above.