let y = logx (x^2 - 5x + 6)
x^y = x^2 - 5x + 6
ln both sides
ln (x^y) = ln(x^2 - 5x + 6)
y lnx = ln(x^2 - 5x + 6)
differentiate implicityly
y(1/x) + (lnx) dy/dx = (2x-5)/(x^2-5x+6)
dy/dx = ((2x-5)/(x^2-5x+6) - y/x)/lnx
Find f'(x) if f(x)= Logx(x^2-5x+6)
NOTE:
that logx is a sub x
1 answer