let 2b - 1= x
2b = x+1
b = (x+1)/2
then for
f(2b-1) = 6b = 2
f(x) = 6(x+1)/2 + 2
=3(x+1) + 2
= 3x + 5
f(x) = 3x + 5
check by replacing x with 2b-1
f(2b-1) = 3(2b-1) +5 = 6b -3+5
= 6b + 2 , as given
Find f(x), if f(2b-1)=6b+2
1 answer