find f'(x)=
f(x)=∫[1,x] t^t dt
3 answers
Edit: the upper limit is actually x^2. Please help!
the value of the function at t = x^2
= (x^2)^x^2
= (x^2)^x^2
The system I'm using says that's wrong What's the process? I don't know how to find the derivative of an integral like this
1 answer