Ask a New Question
Search
find f'(x)
-4x^2 lnx
1 answer
just use the product rule:
f = -4x^2 * lnx
f' = -8x * lnx + (-4x^2)*(1/x)
= -8x*lnx - 4x
= -4x(2lnx + 1)
Ask a New Question
or
answer this question
.