Find (f −1)'(a). f(x) = 3x^3 + 2 sin x + 3 cos x, a = 3

I don't know how to solve this question

2 answers

f'(x) = 9x^2 + 2cosx
f(0) = 3
so (f-1)'(3) = 1/f'(0) = 1/2
ah ty!