f'(x) = 9x^2 + 2cosx
f(0) = 3
so (f-1)'(3) = 1/f'(0) = 1/2
Find (f −1)'(a). f(x) = 3x^3 + 2 sin x + 3 cos x, a = 3
I don't know how to solve this question
2 answers
ah ty!
I don't know how to solve this question
2 answers