by l'Hospital,
(a) -> (1/x + 2)/(2x) -> 3/2
(b) -> 2x/e^x -> 2/e^x -> 0
Find each limit:
(a) lim x->1 (ln(x)+2x-2)/(x^2-1)
(b) lim x->infinity (x^2)/(e^x)
1 answer
(a) lim x->1 (ln(x)+2x-2)/(x^2-1)
(b) lim x->infinity (x^2)/(e^x)
1 answer