find dy/dx

y=3u^2-6u+2,u=v^2-1;v=2x

1 answer

dy/du = 6u - 6
du/dv = 2v
dv/dx = 2

dy/dx = (dy/du)(du/dv)(dv/dx)
= (6u-6)(2v)(2)
= 24v(u-1)

If necessary, use substitution of the originals to express in terms of whichever variable you want