Find dy/dx for y^3 -x^2=2xy

Answer 1

y^3 - x^2 = 2xy
3y^2 dy/dx - 2x = 2x dy/dx + 2y
dy/dx(3y^2 - 2x) = 2y + 2x

dy/dx = 2(x+y)/(3y^2 - 2x)