Find dy/dt if x=sqrot7/8 and x^2+ y^3=1 and dx/dt=2.

Answer 1

x^2+ y^3=1
2x dx/dt + 3y^2 dy/dt = 0
when x=√(7/8), y = 1/2, so now we have
2√(7/8) * 2 + 1/8 dy/dt = 0
dy/dt = 16√(7/2)