y = x^2+3
dy/dt = 2x dx/dt = 2*1*4 = 8
Find
dy/dt
at x = 1 and y = x2 + 3 if
dx/dt
= 4
I'm not sure how to set up this type of equation. Do you use the pythagorem theorem for this? Then take the derivative, and then plug in?
1 answer