Since P1 is in quadrant 4, its coordinates will be in the form of (x, -y) where x > 0 and y > 0. Similarly, since P2 is in quadrant 3, its coordinates will be in the form of (-x, -y) where x > 0 and y > 0.
Let's assume the coordinates are:
P1 = (x1, -y1) and P2 = (-x2, -y2)
Using the distance formula, the distance between P1 and P2 can be calculated as:
Distance = sqrt((x2 - x1)^2 + (-y2 + y1)^2)
Therefore, the distance between P1 and P2 can be found using the coordinates provided.
Find distance between P1 and P2.
4 quadrant graph. P1 is in quadrant 4, P2 is in quadrant 3
Find distance between P1 and P2.
4 quadrant graph. P1 is in quadrant 4, P2 is in quadrant 3
1 answer