If a number is divisible by 9, the sum of its digits is too. That is, they must add up to a multiple of 9.
6+A+B = 9k
so,
A+B = 9k-6
The most they can be is 18, so they must add up to 12 or 3.
3B must be a multiple of 4, since xxx00 is. So, 3B must be 32 or 36. Can't be 36, because that would make B=6 so A=6.
So, B = 2 and A=1
12132 = 4*3283 = 9*1348
Find digits A and B in the number below so the folling condition are true. The 5-digit number must be divisible by 4. The 5-digit number must be divisible by 9. Digit A cannot be the same as Digit B.
12A3B
Explain the steps you followed to solve the problem.
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