g ' (Ø) = 2cos(2Ø -1) (2)
= ...
Find derivative of:
g(theta) = cos^2(2theta-1)
3 answers
hmmm. power rule, then chain rule twice
yup, forgot about the exponent, Steve is right
g ' (x) = 2 cos(2Ø-1) (-sin(Ø-1)) ( 2)
= -4 sin(2Ø-1)cos(2Ø-1)
which they might have changed to
-2 sin(4Ø-2)
g ' (x) = 2 cos(2Ø-1) (-sin(Ø-1)) ( 2)
= -4 sin(2Ø-1)cos(2Ø-1)
which they might have changed to
-2 sin(4Ø-2)