Find cot x if sin x cot x csc x = .square root 2

Question

After reducing i got cot= square root of 2

Am i correct?

Answer 1

Yes, since
sinx cotx cscx = sqrt2 is equivalent to cotx = sqrt2
x = 45 degrees

Answer 2

x=arccot(sqrt2)=35 degrees (approx)

Answer 3

+180*n

Answer 4

My x value was wrong. I was confusing sec with cot

x = 35.3 degrees