Ask a New Question

Find coordinates of the points on the given curve at which it's gradient has the given value.

Y=x^3+x^2
Gradient = 1

I know that
dy/dx = 3x^2+2x

I'm not sure what to do next.

Please help
Thankyou 😘

1 answer

Well, when is that slope equal to 1 ?

3 x^2 + 2 x - 1 = 0

(3x-1)(x+1) = 0

x = 1/3 or x = -1

Ask a New Question or answer this question.

Similar Questions

A curve is given by the equation y = x/(x - 1). The coordinates of a point P on the curve are (3, 1 1/2). Show that the gradient
1. 3 answers
Point P in the curve y=x^3 has coordinates (3,27) and PQ is the tangent to the curve at P.Point Q touches the x-axis.Find the
1. 2 answers
The equation of a curve is y=px+ h/x^3 ,(x not equal to 0) where h and k are constants. Thegradient of the curve y at the point
1. 2 answers
Find the coordinates of the point on the curve y=x³-3x²+6x+2 at which the gradient is 3
1. 1 answer

more similar questions