Find arc length of y=logx from x=1 to x=2.
dy/dx)^2=1/x^2
arc length=Int of [sqrt(1+1/x^2)]dx
=Int of [sqrt(1+x^2)/x^2]
=Int of [sqrt(1+x^2)]/x from x=1 to x=2.
How to proceed further to integrate?
dy/dx)^2=1/x^2
arc length=Int of [sqrt(1+1/x^2)]dx
=Int of [sqrt(1+x^2)/x^2]
=Int of [sqrt(1+x^2)]/x from x=1 to x=2.
How to proceed further to integrate?
3 answers
0 answers
1 answer
2 answers