Fr = F1 + F2 + F3 + F4.
Fr = 20[45o] + 15[135o] + 5[[225o] + 10[315o]
Fr = 14.14+14.14i + 10.61-10.61i -3.54-3.54i
+7.07-7.07i,
Fr = 28.28 - 7.08i = 29.16kg[-14.1o] = 29.16kg[14.1o] S. of E.
Find analytically the resultant of the forces shown below:
Where: F1 = 20 kg (4,4)
F2 = 15 kg (-5,5)
F3 = 5 kg (-2,-2)
F4 = 10 kg (3,-3)
1 answer