For 40 the prime factorization is:
2³ ∙ 5¹
For 1400 the prime factorization is:
2³ ∙ 5² ∙ 7¹
Since x is an odd number, the factor 2³ must be discarded.
The number x can be written as:
x = 5ᵐ ∙ 7ⁿ
where
m ≤ 2
because in factorization the largest exponent of the number 5 is two
n ≤ 1
because in factorization the largest exponent of the number 7 is one
By testing these values you get:
For m = 0 , n = 0
x = 5⁰ ∙ 7⁰ = 1 ∙ 1 = 1
LCM of 1 and 40 is 40
For m = 0 , n = 1
x = 5⁰ ∙ 7¹ = 1 ∙ 7 = 7
LCM of 7 and 40 is 280
For m = 1 , n = 0
x = 5¹ ∙ 7⁰ = 5 ∙ 1 = 5
LCM of 5 and 40 is 40
For m = 1 , n = 1
x = 5¹ ∙ 7¹ = 5 ∙ 7 = 35
LCM of 35 and 40 is 280
For m = 2 , n = 0
x = 5² ∙ 7⁰ = 25 ∙ 1 = 25
LCM of 25 and 40 is 200
For m = 2 , n = 1
x = 5² ∙ 7¹ = 25 ∙ 7 = 175
LCM of 175 and 40 is 1400
So x = 175
Find an odd natural number x such that LCM (x, 40) = 1400
4 answers
INTERESTING
it is very compiecatid try to esay it
odd means = 2n +1
then 1400 = 40x = 40( 2n + 1)
then 1400/40 = x/2n + 1
35 = x/2n +1
x = 35(2n + 1)
test n with small number start from 0
n = 0 - - - - - - - - x = 35 it does't give 1400 when we take LCM
n = 1 -------- ------ x = 105 it satisfy all the property
n = 2 ---------------x = 175 " " " " " " "
then 1400 = 40x = 40( 2n + 1)
then 1400/40 = x/2n + 1
35 = x/2n +1
x = 35(2n + 1)
test n with small number start from 0
n = 0 - - - - - - - - x = 35 it does't give 1400 when we take LCM
n = 1 -------- ------ x = 105 it satisfy all the property
n = 2 ---------------x = 175 " " " " " " "