Find an equation of the tangent line to the graph y=(x^3 + 2)^5 at x= -1

Answer 1

dy/dx = 5(x^3 + 2)^4 (3x^2)

sub in x = -1 to find the slope of the tangent
sub x = -1 into original to get the corresponding y

Now that you have the slope and a point on the tangents, the equation is readily found

Let me know what you got

Answer 2

Find the value of y and dy/dx (the slope, m) at x' = -1. Call that value y'. Obviously y' = 1.
dy/dx is harder.

Then write the function in the form

m = (y - y')/(x - x')