Find an equation of the tangent line to the graph of y = e^(−x^2) at the point (5, 1/(e^25)).

Question

My work:

y' = -2xe^(-x^2)

y' when x = 5 = -10e^25

y - (1/e^25) = -10e^25 * (x - 5)

y = (-10e^25) (x - 5) + (1/e^25)

This is incorrect. How?

Answer 1

y' when x = 5 = -10e^-25