the slope is -14x/(x^^2+3)^2, so at (2,1) the slope is -28/49 = -4/7
Now you have a point and a slope, so the line is
y-1 = -4/7 (x-2)
See the graphs at
http://www.wolframalpha.com/input/?i=plot+y%3D7%2F(x%5E2%2B3),+y+%3D+-4%2F7+(x-2)%2B1
Find an equation of the tangent line to the graph at the given point. (The graph is called a Witch of Agnesi.)
f(x)= 7 / x^2 + 3
(2,1)
1 answer