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Original Question
find an equation of the tangent line to the curve y = x √x that is parallel to the line y = 1 + 3x.Asked by Anonymous
find an equation of the tangent line to the curve y= x(x)^(1/2) that is parallel to the line y=1+3x
Answers
Answered by
drwls
The slope dy/dx of your straight line is 3.
Find the x value corresponding where dy/dx = 3
(for the first y(x) equation)
The meaning of
y= x(x)^(1/2)
is unclear.
Do you mean x*x^(1/2) = x^(3/2) ?
Find the x value corresponding where dy/dx = 3
(for the first y(x) equation)
The meaning of
y= x(x)^(1/2)
is unclear.
Do you mean x*x^(1/2) = x^(3/2) ?
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