y' = 6e^x(cosx - sinx)
y'(0) = 6(1-0) = 6
so, you have a point and a slope. The rest is just algebra I.
Find an equation of the tangent line to the curve at the given point.
y = 6e^x cos x, (0, 6)
1 answer
y = 6e^x cos x, (0, 6)
1 answer